求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/18 02:47:25
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,求1-cos^6x-sin^6x/1-cos^4x-sin^
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
(1-cos^6x-sin^6x)/(1-cos^4x-sin^4x)
=[1-(cos^6x+sin^6x)]/[1-(cos^4x-sin^4x)]
=[1-(cos^2x+sin^2x)(cos^4x-cos^2xsin^2x+sin^4x)]/[1-(cos^2x-sin^2x)(cos^2x+sin^2x)]
=[1-(cos^4x-cos^2xsin^2x+sin^4x)]/[1-(cos^2x-sin^2x)]
=[1-(cos^4x+2cos^2xsin^2x+sin^4x-3cos^2xsin^2x)]/[1-cos^2x+sin^2x]
={1-[(cos^2x+sin^2x)^2-3cos^2xsin^2x]}/[sin^2x+sin^2x]
={1-[1-3cos^2xsin^2x]}/(2sin^2x)
=(1-1+3cos^2xsin^2x)/(2sin^2x)
=3cos^2xsin^2x/(2sin^2x)
=3cos^2x/2
求(1-sin^6x-cos^6x)/(1-sin^4x-cos^4x)的值
求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值,
化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x
化简(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x)
求值：(1-sin^6 x-cos^6 x)/(1-sin^4 x-cos^4 x)
已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x
cos x/sin x+sin x/(1+cos x) 化简.
证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)]
化简（1)√3sin x+cos x (2）√2(sin x-cos x) （3）√2cos x-√6sin x
已知sin(x+π/3)=1/4,求sin(2π/3-x)+cos²(π/6-x)
f'(sin x)=1-cos x 求f''(x)
1/cos(x) - tan(x) = 3 求sin(x)1/cos(x) - tan(x) = 3求sin(x)
第一题1/2cos x-√3/2sin x 第二题√3sin x+cos x 第三题√2[sin x-cos x] 第四题√2cos x-√6sin x
(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急)
求证：1-cos^4x-sin^4x/1-cos^6x-sin^6x=2/3
证明1-sin^6x-cos^2x/1-sin^4x-cos^4x=3/2
sin(x+π/6)=1/2,求cos(π/3-x)
sin(x/2+派/6)=1/2,求cos(x+派/3)