matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
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matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
matlab求函数曲线的积分 请问,怎么弄才能出真确结果
syms x t
f1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)
int(f1,x)
f1 =
((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)
Warning:Explicit integral could not be found.
ans =
int(((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2),x)
matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
积分后,得到
-1/2*(1-cos(2*pi/t*(x-350))^2)^(1/2)*EllipticE(cos(2*pi/t*(x-350)),310*pi*(-1/t^2)^(1/2))/sin(2*pi/t*(x-350))/pi*t
式中,EllipticE为椭圆函数