若x^2-y^2=28,x+y=7,则x-y=
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若x^2-y^2=28,x+y=7,则x-y=若x^2-y^2=28,x+y=7,则x-y=若x^2-y^2=28,x+y=7,则x-y=x²-y²=(x+y)(x-y)=28x+
若x^2-y^2=28,x+y=7,则x-y=
若x^2-y^2=28,x+y=7,则x-y=
若x^2-y^2=28,x+y=7,则x-y=
x²-y²=(x+y)(x-y)=28
x+y=7
所以 x-y=28÷7=4
x^2-y^2=28
∴(x+y)(x-y)=28
∵x+y=7
∴7(x-y)=28
x-y=4
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