已知(x+y)^2=19 (x-y)^2=15 求xy与x^2+y^2的值
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已知(x+y)^2=19(x-y)^2=15求xy与x^2+y^2的值已知(x+y)^2=19(x-y)^2=15求xy与x^2+y^2的值已知(x+y)^2=19(x-y)^2=15求xy与x^2+
已知(x+y)^2=19 (x-y)^2=15 求xy与x^2+y^2的值
已知(x+y)^2=19 (x-y)^2=15 求xy与x^2+y^2的值
已知(x+y)^2=19 (x-y)^2=15 求xy与x^2+y^2的值
由(x+y)^2=19.和(x-y)^2=15
所以 (x+y)^2-(x-y)^2=x^2+2xy+y^2-x^2+2xy-y^2=4xy
故 4xy=19-15=4
则 xy=1
由 x^2+y^2=x^2+2xy+y^2-2xy=(x+y)^2-2xy=19-2=17
题目检查下先~~ (x+y)^2=19 (x-y)^2=15
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