提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/19 13:02:04
提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解提公因式(x+y-z)(x-y+z)+(y-
提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解
提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)
这是因式分解
提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解
(x+y-z)(x-y+z)+(y-x-z)(y-x+z)
=-(x+y-z)(-x+y-z)+(y-x-z)(y-x+z)
=(y-x-z)<-(x+y-z)+(y-x+z)>
=2(y-x-z)(-x+z)
2x(x-y+z)
2x(x-y+z)
(x+y-z)(x-y+z)+(y-x-z)(y-x+z)
=(x+y-z)(x-y+z)+(-1)*(-1)*(y-x-z)(y-x+z)
=(x+y-z)(x-y+z)-[(-1)*(y-x-z)](y-x+z)
=(x+y-z)(x-y+z)-(x-y+z)(y-x+z)
=(x-y+z)[(x+y-z)-(y-x+z)]
=(x-y+z)(x+y-z-y+x-z)
=(2x-2z)(x-y+z)
=2(x-y)(x-y+z)
(x+y-z)(x-y+z)+(y-x-z)(y-x+z)
=(x+y-z)(x-y+z)-(x-y+z)(y-x+z)
=(x-y+z)(x+y-z-y+x-z)
=2(x-y+z)(x-z)
原式=(x+y-z)(x-y+z)-(x-y+z)(y-x+z)
=(x-y+z)(x+y-z-y+x-z)
=(x-y+z)(2x-2z)
=2(x-y+z)(x-z)
提公因式(x+y-z)(x-y+z)+(y-x-z)(y-x+z)这是因式分解
x(x-y-z)+y(y-x+z)+z(z-x+y) 提取公因式法
数学 多项式(x+y-z)(x-y+z)-(y+z-x)(z-x-y)公因式如题 求公因式
(x+y+z)的二次方-(x-y-z)的二次方提公因式
(x+y-z)(x-y+z)-(y+z-x)(z-x-y)的公因式是?
将(x+y-z)²(x+y+z)-(y+z-x)(z-x-y)²用提公因式法分解因式.
分解因式:(1):x(x-y)+y(y-X) 多项式(x+y-z)(x-y+z)-(y+z-X)(Z-x-y)的公因式是多少?
提公因式法(急!(x+y+z)(x-y+z)+(y-x+z)(y-x-z)和a(a-b-c)+b(c-a+b)+c(b-a+c)怎麽用提公因式法计算?
(x+y-z)(x-y+z)-(y+z-x)(z-x-y)公因式 过程(x+y-z)(x-y+z)-(y+z-x)(z-x-y)=(x+y-z)(x-y+z)+(y+z-x)为什么变成加号只有后面的变号
用提公因式法分解因式:(x^2-xy)+z(x-y)
急!求解提公因式法的几道题1.(x+y-z)(x-y+z)-(y+z-x)(z-x-y)的公因式是什么?写过程2. 2xy+3 y的平方为什么 没有公因式,解释系数为什么不行.3. 各组多项式中没有公因式的是:说理由 ax-bx与 by-ay
x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) +z-x/(y-z)(y-x)
x^-(y-z)^/(x+y)^-z^
计算(x+y-z)(x-y-z)
计算:(x-y+z)(-x+y+z)
(x+y-z)(x-y+z)=
x y y ...y z x y ...y z z x ...y ........z z z ...x 求解行列式.
x+y>z 0