7.定义：double x=3.5,y=3.2;则表达式(int)x*0.5的值是 ,表达式y+=x++的值是 .

c++习题 10.下列函数定义中正确的是( ).请解析一下每个选项.还有正确答案A.double fun(double &x,double &y) B.double fun(double &x,double &y){ {double z; return *x/*y;z=x/y; }return z;}C.double fun(double *x,double *y) D.double 7.定义：double x=3.5,y=3.2;则表达式(int)x*0.5的值是 ,表达式y+=x++的值是 . 【C语言】 double型变量定义x和y为double型变量,则表达式x=1,y=x+3/2的值是多少? 定义一个Point类并用成员函数 double Distance(const& Point)求两点间距离#include#includeusing namespace std;class Point{private:double X,Y;public:Point(double x,double y){X=x;Y=y;}//构造函数double GetX(){return X;}double GetY(){retu class Point{ private double x; private double y; Point(double x1,double y1){ x=x1; y=y1; } public #includeusing namespace std;double tiaohe (double,double);int main(){double x,y;coutx>>y&&x*y!=0) {double t_tiaohe=tiaohe(x,y);cout 类定义为什么要这样class point{public:double x,y;point(){};point(double x1,double y1){x=x1;y=y1;}//向量赋值double operator%(const point &a)//叉积{return x*a.y-y*a.x;}double operator*(const point &b)//点积{return x*b.x+y*b.y;}point ope 2.以下正确的函数定义是 .A）double fun(int x,int y) B）double fun(int x,y)所谓 { int z ; return z ;}C）fun (x,y) D）double fun (int x,int y){ int x,y ; double z ; { double z ;z=x+y ; return z ; } return z ; } 已知有如下类的定义:public class Point { private double x,y; public Point(double a,double b) { x=a;y=b; }public double getX(){return x;}public double getY(){return y;}} 编写一个测试类 TestPoint,在此类中定义一个方法,此方法 若已定义：int x=11; double y=3.5; 则表达式 y/2+x%2/2的值为什么 是1.75 为什么在s=s+x/y中需要把x,y定义为double型才能计算正确? 以下函数定义中正确的是 （）以下函数定义中正确的是 （） .A.double fun(double x,double y){ } B.double fun(double x;double y){ }C.double fun(double x,double y);{ } D.double fun(double x,y){ }A.double fun(double x,double y){ } B double x=1.52,y=5. 有下列函数定义：int fun (double a,double b) {return a*b;}有下列函数定义：int fun (double a,double b){return a*b;}若有下列选项中所用变量都已经正确定义并赋值,错误的函数调用是（ ）z=fun(fun(x,y)x,y) 求详 double pow(double x,double y) C语言#include#includeint main(){double pn[5],t[5],p0=10000;t[0]=double pow(double 1.50,double 2.0);pn[0]=p0*t[0];t[1]=double pow(double 4.10,double 8.0);pn[1]=p0*t[1];t[2]=double pow(double 4.30,double 4.0);pn[2]=p0*t[ java问题..谢谢lass Point { double x,y,z; Point(double _x,double _y,double _z) { x = _x; y = _y;class Point {double x,y,z;Point(double _x,double _y,double _z) {x = _x;y = _y;z = _z;}void setX(double _x) {x = _x;}double getDistance(Point p) {return 3、以下正确的函数定义是( ).A.double fun(int x,int y); {int z; z=x+y; return z；}3、以下正确的函数定义是( ).A.double fun(int x,int y); {int z; z=x+y; return z；}B.fun(int x,y) {int z; return z；}C.double fun( 若已定义：int x=2,y=4; 则表达式(double)x/y+y%x的值是（ ）