已知0<β<π/4<α<3π/4,cos(π/4+α)=3/5,sina(3π/4+β)=5/13,求sina(2α+2β)的值已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求sina(α+β)的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 23:26:57
已知0<β<π/4<α<3π/4,cos(π/4+α)=3/5,sina(3π/4+β)=5/13,求sina(2α+2β)的值已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求sina(α+β)的值
已知0<β<π/4<α<3π/4,cos(π/4+α)=3/5,sina(3π/4+β)=5/13,求sina(2α+2β)的值
已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求sina(α+β)的值
已知0<β<π/4<α<3π/4,cos(π/4+α)=3/5,sina(3π/4+β)=5/13,求sina(2α+2β)的值已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求sina(α+β)的值
cos(π/4-α)=3/5
π/4
-π/2<π/4-α<0 -π<π/2-2α<0
3π/4<3π/4+β<π 3π/2<3π/2+2β<2π
cos(π/4+α)=3/5 sin(π/4+α)=-4/5 sin(π/2+2α)=-24/25
cos(π/2+2α)=1/25
sin(3π/4+β)=5/13 cos(3π/4+β)=-12/13 sin(3π/2+2β)=-120/...
全部展开
-π/2<π/4-α<0 -π<π/2-2α<0
3π/4<3π/4+β<π 3π/2<3π/2+2β<2π
cos(π/4+α)=3/5 sin(π/4+α)=-4/5 sin(π/2+2α)=-24/25
cos(π/2+2α)=1/25
sin(3π/4+β)=5/13 cos(3π/4+β)=-12/13 sin(3π/2+2β)=-120/169
cos(3π/2+2β)=49/169
sin(2α+2β)= sin(π/2+2α)cos(3π/2+2β)+sin(3π/2+2β)cos(π/2+2α)
收起