(1)1/2c²d+1/3cd²(2)3/2m-n-2m-n/(2m-n)²(3)a/a²-b²-1/a+b
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(1)1/2c²d+1/3cd²(2)3/2m-n-2m-n/(2m-n)²(3)a/a²-b²-1/a+b(1)1/2c²d+1/3cd&
(1)1/2c²d+1/3cd²(2)3/2m-n-2m-n/(2m-n)²(3)a/a²-b²-1/a+b
(1)1/2c²d+1/3cd²
(2)3/2m-n-2m-n/(2m-n)²
(3)a/a²-b²-1/a+b
(1)1/2c²d+1/3cd²(2)3/2m-n-2m-n/(2m-n)²(3)a/a²-b²-1/a+b
(1)1/2c²d+1/3cd²
=(3d+2c)/(6c²d²)
(2)3/2m-n-2m-n/(2m-n)²
=3/(2m-n)-1/(2m-n)
=2/(2m-n)
(3)a/a²-b²-1/a+b
=(a-a+b)/(a²-b²)
=b/(a²-b²)
如第二题,看不出你要干什么?