2x^2-6y^2+3z^2-xy+7xz+7yz求次式待定系数法解法,

代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答 已知4x-3y=6z 2x+4y=14z 求2xy/x^+y^ 已知4x-3y=6z 2x+4y=14z 求2xy/x^+y^ 分解因式-6x^3y^2z+12x^2y^2z^2+18xy^2z^3 化简x^2-yz/[x^2-(y+z)x+yz]+y^2-zx/[y^2-(z+x)y+zx]+z^2-xy/[z^2-(x+y)z+xy] (2X+Z-Y)/(X^2-XY+XZ-YZ)-(Y-Z)/(X^2-XY-XZ+YZ) 若x+y=6,xy=-8,求代数式(x+y-z)^2+(x+y-z)(x+y+z)-2·z(x-y) 2分之一(x+y+z)的平方＋2分之一（x-y-z)(x-y+z)-z(x+y),其中x-y=6,xy=21 若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值 求证：(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于（xy+yz+zx)/2 已知实数x,y,z,满足那么x+y=6,z^2=xy-9,求(x+y)^z x²-y²+5x+3y+4（x+y-2xy)(x+y-z)+(xy-1）² (xy-1)^2+(x+y-z)(x+y-zxy)因式分解 若|x-3|+|y+2|+|2z+1|=0,求(xy-yz)(y-x+z) 已知｛X-3Y+7z=0,x-2y+4Z (xy不等于0）.求X:Y:ZX-2Y+4Z=0