求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2
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求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2求证:(
求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2
求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2
求证:(x^3/x+y)+(y^3/y+z)+(z^3/z+x)大于等于(xy+yz+zx)/2
证明:
x、y、z>0,依Cauchy不等式,得
(x^2+y^2+z^2)(y^2+z^2+x^2)>=(xy+yz+zx)^2
--->x^2+y^2+z^2>=xy+yz+zx.
故对原式再用Cauchy不等式,得
[x(x+y)+y(y+z)+z(z+x)][x^3/(x+y)+y^3/(y+z)+z^3/(z+x)]>=(x^2+y^2+z^2)^2
--->x^3/(x+y)+y^3/(y+z)+z^3/(z+x)>=(x^2+y^2+z^2)^2/(x^2+y^2+z^2+xy+yz+zx)
--->x^3/(x+y)+y^3/(y+z)+z^3/(z+x)>=(xy+yz+zx)^2/(2xy+2yz+2zx)
--->x^3/(x+y)+y^3/(y+z)+z^3/(z+x)>=(xy+yz+zx)/2.
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