用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
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用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
用消元法解方程组
x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.
x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
题目有问题,把原题拍下来再上传吧
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方程组3x1+x2+x3
用消元法解方程组x1+x2-2x2=-3,5x1-2x2+7x3=22.2x1-5x2+4x3=4 是字母x.x1+2x2-x3-2x4=0,2x1-x2-x3+x4=1,3x1+x2-3x3-x4=1
matlab解超定方程组2x1+x2=3x1+2x2=4x1+x2=5请问这个方程组怎么用MATLAB程序怎么写啊
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具体写出方程组:2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解
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