cos^2 80°+sin^2 50°-sin190°cos320°
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cos^280°+sin^250°-sin190°cos320°cos^280°+sin^250°-sin190°cos320°cos^280°+sin^250°-sin190°cos320°cos^
cos^2 80°+sin^2 50°-sin190°cos320°
cos^2 80°+sin^2 50°-sin190°cos320°
cos^2 80°+sin^2 50°-sin190°cos320°
cos^2 80°+sin^2 50°-sin190°cos320
=sin10^2+sin50^2-sin(180+10)cos(360-40)
=sin10^2+cos40^2+sin10cos40
设sin10=x,cos40=y
=x^2+y^2+xy
=(x+y)^2-xy
sin^2 30°+cos()=1
3-cos 20°/2-sin ^2 80°等于
sin^2 80°为什么等于 cos^2 10°?
(cos^2 10°-cos^2 80°)+sin^2 20°
(cos 10)^2+(cos 50)^2-sin 40 * sin 80 怎么算
利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ
化简 (1+sin a+ cos a)(sin a/2 - cos a/2) / √(2+2cos a)(180°
cos^2 80°+sin^2 50°-sin190°cos320°要求值.
cos^2 80°+sin^2 50°-sin190°cos320°
化简:(1)(cos²10°-cos²80°)²+cos²70°=? (2)(sinα-cosα)²+sin4α/2cos2α=
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sin^2(20)-sin^2(25)sin(20)+cos^2(50)+cos^2(25)sin20
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