24x^2-50x+24=0 ,
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24x^2-50x+24=0,24x^2-50x+24=0,24x^2-50x+24=0,原方程为:24x^2-50x+24=0即:12x^2-25x+12=0即:(3x-4)(4x-3)=0即:3x
24x^2-50x+24=0 ,
24x^2-50x+24=0 ,
24x^2-50x+24=0 ,
原方程为: 24x^2-50x+24=0
即:12x^2-25x+12=0
即:(3x-4)(4x-3)=0
即:3x-4=0或者:4x-3=0
所以:x=4/3或者:x=3/4
X(X+1)(X+2)=24
=(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+25x^2+10x^2-50x+24 这是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24
=(x^2-5x+4)(x^2-5x+6) =(x^2-5x)^2+10(x^2-5x)+24 是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24不好意思我弄错了,是=(x^2-5
X^3-7X^2+18X-24=0
-x^3-3x^2+10x+24=0
x^4-5x^2+10x+24=0
一元二次方程解答!x(5x+4)=5x+44x^2-45=31x-3x^2+22x-24=0(x+8)(x+1)= -12(3x+2)(x+3)=x+14
给50分 今天就要用分式法x^+10X+16=0 16x^-24x+9=0 x^2-4根号2x+9=0 3x^2+10=2x^2+8x
x^2+14x-24=0
x^2-25x+24=0
x^2-10x-24=0
(X^+X)(X^+X-14)+24=0 ^代表平方
x*x+2x=24 ,x=?
解方程(x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0
x×x--2x=24 x等于多少?
(x+1)(x+2)(x+3)(x+4)=24
2x乘以x乘以x=24,求x!
(x+1)(x+2)(x+3)(x+4)=24