2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(解方程,
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2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(解方程,2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(
2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(解方程,
2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(解方程,
2006-x/2005+2008-x/2007=2010-x/2009+2012-x/2011(解方程,
2006-x)/2005+(2008-x)/2007=(2010-x)/2009+(2012-x)/2011
1+(1-x)/2005+1+(1-x)/2007=1+(1-x)/2009+1+(1-x)/2011
(1-x)/2005+(1-x)/2007=(1-x)/2009+(1-x)/2011
(1-x)[1/2005+1/2007-1/2009-1/2011]=0
所以1-x=0
x=1
若x^3+x^2+x+1=0,求x^2008+x^2007+x^2006+x^2005的值
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
当x=1时,x^2006-x^2005+x^2004-x^2003+x^2002-……+x^2-x
1/(x+1)(x+2)+1/(x+2)(x+3)+(x+3)(x+4)+.+1/(x+2005)(x+2006)=1/2x+4012 求X
化简求值:1/x(x+1)+1/(x+)(x+2)+.1/(x+2005)(x+2006),其中X=1.
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)=1/2x+4024
1/(x+1)(x+2) + 1/(x+2)(x+3) + 1/(x+3)(x+4) + ...+ 1/(x+2005)(x+2006) = 1/2x+4012
1/(x+1)(x+2) + 1/(x+2)(x+3) + 1/(x+3)(x+4) + ...+1/ (x+2005)(x+2006) = 1/2x + 4012
1/(x+1)(x+2) + 1/(x+2)(x+3) + 1/(x+3)(x+4) …… 1/(x+2005)(x+2006)=1/2x+4012
1+x+x^2+...+x^2004+x^2005=0 求x^2006
已知1+x+x^2+.+x^2004+x^2005=0,则x^2006=_____
若x^2=x-1,则x^2008-x^2007+x^2006的值是?
(1)2^46-1能被60至70之间的两个数整除,求这两个数.(2)已知1+X+X^2+X^3+X^4=0,求1+X+X^2+X^3+X^4+……+X^2005+X^2006+X^2007+X^2008+X^2009的值.
解方程x-2/2006+x/2007+x+2/2008(x-2)/2006+x/2007+(x+2)/2008
(X-2)/2006 +X/2007 +(X+2)/2008X-2....X....X+2................---- + ---- + -----................2006 2007 2008
解方程(x-2004)/(x-2005)-(x-2005)/(x-2006)=(x-2007)/(x-2008)-(x-2008)/(x-2009)会有赏分的~
已知x^2007=2,则(x^2006+x^2005+x^2004+...+x+1)(x-1)的值
1+x+x^2=0,求x^2007+x^2006+x^2005+...+x+1的值不要只有答案,