[(n+52.8)*5-3.9343]/0.5-10n等多少?

[(n+52.8)*5-3.9343]/0.5-10n等多少? 〖(n+52.8)×5-3.9343〗÷0.5-n×10=? 2^n*3^n*5^n+2/30^n 2^n*3^n*5^(n+1)/30^n 3(n-1)(n+3)-2(n-5)(n-2) Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗? n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10这道题怎么解 1/[n(n+1)]+1/[(n+1)(n+2)]+1/[(n+2)(n+3)]+1/[(n+3)(n+4)]+[(n+4)(n+5)}怎么算谢谢了, 1+(n+2)+(2n+3)+(3n+4)+(4n+5)+……((n-1)n+n)的答案 如果正整数n使得［n/2]+[n/3]+[n/4]+[n/5]+[n/6]=69,则n= 如果正整数n使得［n/2]+[n/3]+[n/4]+[n/5]+[n/6]=69,则n= 4^n+4^(n-1)C1/n+4^(n-2)C2/n+...+Cn/n=答案是5^n. 已知n属于N*,且分段函数f(n)=n-2,n>=10 f[f(n+5)],n 已知m,n为正整数,求出满足等式3n+4n+5n+…+（n+2）n=(n+3)n的所有正整数n 如果正整数n使得[n/2]+[n/3]+[n/4]+[n/5]+[n/6]=69,则n为（ ）.（[ n ]表示不超过n的最大整数） 解方程(2n+1)(n+1)n-(2n-21)(n-10)(n-11)=2(2n-9)(n-4)(n-5) -(a^2n)^5 n·n^4-n^2·n^3上课没咋听懂n·n^4-n^2·n^3 lim(3^2n+5^n)/(1+9^n)3^2n or 5^n