5x-3y=16 5x-x=(3+11/3+1)y5x-3y=16 5x-x=(3+11/3+1)y解这个二元一次方程.三加三分之十一加一 怎么可能等于二分之七？一看就是错的！

用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+. （x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y 已知:3x-5y=0,求x/y,x-y/y,x-y/x 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) （5x+3y)(3y-5x)-(4x-y)(4y+x)= (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2 6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5 3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 已知x/5=y/3,则(x/x+y)+(y/x-y)-(yxy/xxx-yxy) 先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5 先化简,再求值:[3x-2/x+y(x+y/3x-x-y)]/(x-y/x),其中5x+3y=0 先化简,再求值 [2/3x - 2/x+y（x+y/3x -x-y）]*x/x-y,其中5x+3y=0 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 {x+y=5{3x-7y=11 3*X=Y X/2=Y/5+11