解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)

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解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)解分

解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)
解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)

解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)
1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)
1/[(x+1)(x+2)]+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)
2(x+2)/[(x+1)(x+2)(x+3)]=(2x+5)/(x+1)(x+4)
2/(x+3)=(2x+5)/(x+4)
2x+8= (2x+5)(x+3)
=2x^2+11x+15
2x^2+9x +7 =0
(2x+7)(x+1)=0
x= -7/2

因式分解啊,合并同内项