{x+y=840;4x+8x+8y=4y+9y+9x帮我算一算,谢谢诸位了,我老是算错!
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/27 14:11:19
{x+y=840;4x+8x+8y=4y+9y+9x帮我算一算,谢谢诸位了,我老是算错!{x+y=840;4x+8x+8y=4y+9y+9x帮我算一算,谢谢诸位了,我老是算错!{x+y=840;4x+
{x+y=840;4x+8x+8y=4y+9y+9x帮我算一算,谢谢诸位了,我老是算错!
{x+y=840;4x+8x+8y=4y+9y+9x
帮我算一算,谢谢诸位了,我老是算错!
{x+y=840;4x+8x+8y=4y+9y+9x帮我算一算,谢谢诸位了,我老是算错!
4x+8x+8y=4y+9y+9x
4x+8(x+y)=4y+9(x+y)
4x=4y+(x+y)
4x=4y+840
x=y+210
代入x+y=840
y+210+y=840
2y=630
y=315
x=y+210=525
这不是一个很简单的二元一次方程组吗? X=525 Y=315
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
4x+8(x+y)=840 4y+9(x+y)=840
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
9y=3x-(x-1),4(x+y)-(2x+4)=8y
[(2x-y)^2-y(y-4x)-8x]其中x=-1/2
若x-y=1 化简(x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16)
[(2x+y)²-y(y+4x)-8x】/4x,其中x=-1,y=2005 急
已知实数x.y满足根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),求x,y
已知x的平方+y的平方-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
已知x²+y²-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
已知x.x+y.y+8x+6y+25=0,求代数式(x.x-4y.y)/(x.x+4xy+4y.y)-x/(x+2y)的值
计算:(x-y)^8÷(y-x)^4×(x-y)
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
因式分解:(x-2y)-4x+8y=4
X+Y=9 8X+4Y=56
x+8y=15 4x+y=29
x+y=16 8x+4y=104