(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)会的赶快答一下啊 写不完完蛋了

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(-1+1/100)x(-1+1/101)x(-1+1/102)x...x(-1+1/2011)+(-1+1/2012)+(-1+1/2013)会的赶快答一下啊写不完完蛋了(-1+1/100)x(-1

(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)会的赶快答一下啊 写不完完蛋了
(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)
会的赶快答一下啊 写不完完蛋了

(-1+1/100)x(-1+1/101)x(-1+1/102)x...x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)会的赶快答一下啊 写不完完蛋了
=(-99/100)×(-100/101)×(-101/102)×……×(-2011/2012)×(-2012/2013)
=99/2013
=3/61

(-1+1/100)x(-1+1/101)x(-1+1/102)x... x (-1+1/2011) +(-1+1/2012)+(-1+1/2013)
=(-1)的1914次方 ×(1-1/100)×(1-1/101)×(1-1/102)×...×(1-1/2010)×(1-1/2011)×(1-1/2012)×(1-1/2013)
=(99/100)×(100/101)×(10...

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(-1+1/100)x(-1+1/101)x(-1+1/102)x... x (-1+1/2011) +(-1+1/2012)+(-1+1/2013)
=(-1)的1914次方 ×(1-1/100)×(1-1/101)×(1-1/102)×...×(1-1/2010)×(1-1/2011)×(1-1/2012)×(1-1/2013)
=(99/100)×(100/101)×(101/102)×...×(2009/2010)×(2010/2011) ×(20011/2012)×(2012/2013) (注:相邻两项分子分母相消)
=99/2013
如果觉得好请采纳下,谢谢!

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答:
2013-100+1=1914项
(-1+1/100)x(-1+1/101)x(-1+1/102)x... x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)
=(-99/100)x(-100/101)x(-101/102)x....x(-2010/2011)x(-2011/2012)x(-2012/2013)
=[(-1)^1914]...

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答:
2013-100+1=1914项
(-1+1/100)x(-1+1/101)x(-1+1/102)x... x (-1+1/2011)+(-1+1/2012)+(-1+1/2013)
=(-99/100)x(-100/101)x(-101/102)x....x(-2010/2011)x(-2011/2012)x(-2012/2013)
=[(-1)^1914]x(99/2013)
=33/671
=3/61
除去第一个分子99和最后一个分母2013外,相邻两项的分子和分母相互抵消

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每项都是负数100~2013 共有偶数项 则 答案为正数
每一项的分母与后一项的分子可以约掉
第一项的分子和最后一项的分母没有项跟他约
答案为99/2013 =33/671=3/61 ~~www

原式=(-99/100)×(-100/101)×(-101/102)×...×(-2010/2011)×(-2011/2012)×(-2012/2013)
因为共有1914个分数,所以是正的
所以原式=99/2013=3/61