若x^2+2x+1+y^2-8y+16=0,求y/x.十万火急!

若x-y=1 化简（x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16) x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 若x*x+y*y=x+y-1/2,求x,y的值如题 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 3分之2(x-y)-4分之x+y=-1 8(x+y)-4(2x-y)=16 16-8（x-y)+(x-y)2 x^+2x+1+y^2-8y+16=0求y/x 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. [(2x-y)^2-y(y-4x)-8x]其中x=-1/2 若变量x,y满足约束条件{x>=-1;y>=x;3x+2y 9y=3x-(x-1),4(x+y)-(2x+4)=8y 已知x^2-8x+y^2-y+16又1/4=0,求[(x+y)(x-y)-(x+y)^2-2y(x-3y)]÷4y的值 若|x+y-1|+（x-y-2)²=0,求代数式（x+2y)(x-2y）-（2x-y)(-y-2x)的值. 若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值? x+y=1 5x-2y=8 3x-y=7 2x-y=3x表示y和用y表示x