y=2sin(2x+π/6)的单调增区间为什么是这样的,

y=2sin(-x)的单调增区间为 y=sin(-2x)的单调增区间 函数y=-3sin(2π-π/6)的单调增区间是函数y=-3sin(2x-π/6)的单调增区间是 y=sin(-2x)+6的单调区间是 y=sin(2x+π/3)单调增区间 y=2sin(2x+π/6)的单调增区间为什么是这样的, 求y=2sin(2x+π/6)的单调增区间 求y=sin(2x+π/6)的周期和单调增区间 求函数y=log2底sin（2x+π/4）的单调增区间和单调减区间. 求函数y=2sin(2x+π/6),x属于(-π,0】的单增区间,求y=cos2x的单调区间,求y=3sin(x/2-π/6)的单调区间 求y=3sin(2x+π/4)的单调递增区间和y=3sin(2x+π/6)的单调递减区间 求y=sin(-2x+π/6)的单调增区间?参考答案这样给的：求y=sin(-2x+π/6)的单调增区间,即求y=sin2x-π/6的增区间!应该是求y=sin(-2x+π/6)的单调增区间,即求y=sin2x-π/6的的减区间! 函数y=sin(x+π/3)的单调增区间是函数y=cos(2x+π/3)的单调增区间是函数y=sin(π/3-x)的单调增区间是 函数y=sin(π+x),x∈[-π/2,π]的单调增区间是 y=cos(3/π+2x)sin(3/π-2x)的单调增区间 求y=sin(2x+π/3)+cos(2x-π/6)的单调区间 y=2sin[(π/6)-2x]的单调递增区间 x属于[0,π] 函数y=sin(x+π/2)cos(x+π/6)的单调递减区间是?