若|2x+y+1|+(x-y+2)^2=0则(x^y*y)^2y+3=谁会算超急

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 若x*x+y*y=x+y-1/2,求x,y的值如题 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. 若变量x,y满足约束条件{x>=-1;y>=x;3x+2y 若|x+y-1|+（x-y-2)²=0,求代数式（x+2y)(x-2y）-（2x-y)(-y-2x)的值. 若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值? 若x-y=1 化简（x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16) 若x+y=4,则多项式1/2(x+y)+4(x-y)-3（x-y）-3/2(x+y)-x+y值是（） 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 若f(x+y,y/x)=x^2-y^2,则F(X,Y)= x+2y=2x+y+1=7x-y 求：2x-y? 二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y