若x^2+y^2-2x+2y-2=0则x、y各是多少
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若x^2+y^2-2x+2y-2=0则x、y各是多少若x^2+y^2-2x+2y-2=0则x、y各是多少若x^2+y^2-2x+2y-2=0则x、y各是多少0=(x^2-2x+1)+(y^2+2y+1
若x^2+y^2-2x+2y-2=0则x、y各是多少
若x^2+y^2-2x+2y-2=0则x、y各是多少
若x^2+y^2-2x+2y-2=0则x、y各是多少
0=(x^2-2x+1)+(y^2+2y+1) =(x-1)^2+(y+1)^2 x=1 y=-1
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