4x+3y=1 2x-5y=7
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4x+3y=12x-5y=74x+3y=12x-5y=74x+3y=12x-5y=74x+3y=1y=(1-4x)/3代入2x-5y=72x-5(1-4x)/3=76x-5+20x=2126x=26所
4x+3y=1 2x-5y=7
4x+3y=1 2x-5y=7
4x+3y=1 2x-5y=7
4x+3y=1
y=(1-4x)/3
代入2x-5y=7
2x-5(1-4x)/3=7
6x-5+20x=21
26x=26
所以
x=1
y=(1-4x)/3=-1
4x+3y=1
2x-5y=7
4x+3y=1
4x-10y=14
13y=-13
y=-1
x=(1+3)/4=1
x=1
y=-1
将二式乘以2,即为 4x-10y=14,然后和一式相减,得到y=-1,x=1.
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