(0.5S+3)/20=(0.5S-3)/18的计算过程

用MATLAB求出G(s)=(s*s+2s+2)/(s*s*s*s+7s*s*s+3s*s+5s+2)的极点 %-15s%-15s%-12s%-15s%-20s%-3s 求原函数x=(2s*s+12s+6)%s(s+2)(s+3) (0.5S+3)/20=(0.5S-3)/18的计算过程 Matlab Simulink操作1.产生幅值、频率为2,基准为0.5的正弦波信号.2.产生传递函数：H1(s)=(2s^3+s^2+5s+1)/(s^3+12s^2+3s+1)H2(s)=4.5(s-1)(s+2)/[s(s-3+2i)(s-3-2i)(s+1)]3.食饵－捕食者模型：设食饵（如鱼、兔等）数量 340m/s分之s-5200m/s分之s=0.5s怎么算? #include mian() { double x,y,z,s; printf(input x,y,z: ); scanf(%lf %lf %lf,&x,&y,&z)#include mian(){ double x,y,z,s; printf(input x,y,z: ); scanf(%lf %lf %lf,&x,&y,&z); s=(x+y+z)/3; s=s*10; s=s+0.5; s=(int)s; s=s/10; printf(s=%f ,s);} S^3+2S^2+2S+3=0 2S/(S/3 S/6)=4表示什么/ 6s+3s一9s=? 如何在matlab中输入形式如:G(s) = 0.5 + 0.5 e(-3s)的传递函数?G(s) = 0.5 + 0.5 *e^(-3s)算式是这样 0.5cm/s=___m/s 0.5cm/s=多少m/s 3s^4+18s^3+38s^2+32s+12=0求s=?s真么算阿? F(s)=(s+6)/(s×s+4s+3)(s+2)拉普拉斯的逆变换该怎么求? clearclcr=0.1;s=0.01;T=0:0.5:20;w=0;f0=(-tanh(r)^0./cosh(r));f1=(-tanh(r)^1./cosh(r));B0=(f0./4)*s*sqrt((0+1)*(0+2)).*(1-cos(2.*T/s));B1=(f1./4)*s*sqrt((0+2)*(0+3)).*(1-cos(2.*T/s));C0=(f0./2)*s*(0+1)*sin(2.*T/s);C1=(f1./2)*s*(0+2)*sin(2.*T/s);w=0.5* cost[N-1][s]=0.5*s+(3+p[N-1][s])*(p[N-1][s]>0);这里的逻辑表达式的具体用法,能否讲下呢? 拉普拉斯变换 F(s)=(s+3)/[(s+1)(s+2)] 求z变换有两题,F(s)=(s+3)/[(s+1)(s+2)] F(s)=1/[s(s^2+1)]求z变换