化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 13:35:27
化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy

化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]
化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]

化简:[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]
[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]
=(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)
=[x(√x+√y)/[y(√x-√y)(√x+√y)]-[x+√(xy)+y]/{(√x-√y)[x+√(xy)+y]}
=x/[y(√x-√y)]-1/(√x-√y)
=(x-y)/[y(√x-√y)]
=(√x-√y)(√x+√y)/[y(√x-√y)]
=(√x+√y)/y