已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=是:(2s-u)分之(v-2s) =(s)分之(v-s)(u,v都是正整数,且u不等于v)则s=

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已知(2s-u)分之(u-2s)=(s)分之(u-s)(u,v都是正整数,且u不等于v)则s=是:(2s-u)分之(v-2s)=(s)分之(v-s)(u,v都是正整数,且u不等于v)则s=已知(2s-

已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=是:(2s-u)分之(v-2s) =(s)分之(v-s)(u,v都是正整数,且u不等于v)则s=
已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=
是:(2s-u)分之(v-2s) =(s)分之(v-s)
(u,v都是正整数,且u不等于v)则s=

已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=是:(2s-u)分之(v-2s) =(s)分之(v-s)(u,v都是正整数,且u不等于v)则s=
式子中没有v哈!
已知(2s-u)分之(u-2s) = (s)分之(u-s),那么:
(2s-u)(u-s)=s(u-2s)
2su-u²-2s²+us=su-2s²
2su-u²=0
2su=u²
s=u/2