已知数列{An}满足A1=2,A(n+1) = (2An) / (An +2)数列{1/An}是否为A.P,说明理由
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已知数列{An}满足A1=2,A(n+1)=(2An)/(An+2)数列{1/An}是否为A.P,说明理由已知数列{An}满足A1=2,A(n+1)=(2An)/(An+2)数列{1/An}是否为A.
已知数列{An}满足A1=2,A(n+1) = (2An) / (An +2)数列{1/An}是否为A.P,说明理由
已知数列{An}满足A1=2,A(n+1) = (2An) / (An +2)
数列{1/An}是否为A.P,说明理由
已知数列{An}满足A1=2,A(n+1) = (2An) / (An +2)数列{1/An}是否为A.P,说明理由
A(n+1) =(2An) / (An +2)
两边同时取倒数 1/A(n+1) = (An +2)/2An
1/A(n+1) = 1/2 + 1/An
1/A(n+1) - 1/An =1/2
故 {1/An } 可以看成是首相为1/A1=1/2,公差为1/2的等差数列
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