1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=
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1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=1/1x2x3+1/2x3x4+1/3x4x5+.+
1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=
1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=
1/1x2x3+1/2x3x4+1/3x4x5+.+1/11x12x13=
原式=﹙1-1／2-1／3﹚+﹙1／2-1／3-1／4﹚+﹙1／3-1／4-1／5﹚+······+﹙1／11-1／12-13／13﹚=1-1／13=12／13
1x2x3+2x3x4+...+nxx=?
1x2=1/3x(1x2x3-0x1x2)2x3=1/3x(2x3x4-1x2x3)3x4=1/3x(3x4x5-2x3x4)求1x2x3+2x3x4+3x4x5+...+7x8x9=?
1x2x3+2x3x4+3x4x5+…+8x9x10
1x2x3+2x3x4+3x4x5+.+10x11x12
1x2x3+2x3x4+3x4x5+...+7x8x9=,
1x2X3+2x3X4+3x4X5+…+7X8X9=?
1x2x3 2x3x4 3x4x5 .10x11x12,怎么算
求和：1X2X3+2X3X4+3X4X5+...+98X99X100
1/1x2x3+1/2x3x4+.+1/98x99x100 .
1/1X2X3+1/2X3x4+…+1/48X49X50
1X2X3+2X3X4+.+n(n+1)(n+2)
1x2x3+2x3x4+.+nx(n+1)(n+2)=?
1x2x3+2x3x4+.+n(n+1)(n+2)=?
求和1x2x3+2x3x4+...+n(n+1)(n+2)
1x2x3+2x3x4+…+n(n+1)
计算1x2x3+2x3x4+…+48x49x50
1x2=1|3(1x2x3-0x1x2) 2x3=1|3(2x3x4-1x2x3) 3x4=1|3(3x4x5-2x3x4)由此推断1x2x3+2x3x4+3x4x5.7x8x9=?
1/1x2x3+1/2x3x4+1/3x4x51/2x3x4 + 1/3x4x5 + 1/4x5x6 +……+1/99x100x101是 1/（2x3x4）