化简：cos(π/3+α)+sin(π/6+α)
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/22 20:57:36
化简：cos(π/3+α)+sin(π/6+α)化简：cos(π/3+α)+sin(π/6+α)化简：cos(π/3+α)+sin(π/6+α)这个可以用和差化积的,只不过要先用诱导公式变一下：比如说
化简：cos(π/3+α)+sin(π/6+α)
化简：cos(π/3+α)+sin(π/6+α)
化简：cos(π/3+α)+sin(π/6+α)
这个可以用和差化积的,只不过要先用诱导公式变一下：
比如说都变成sin的
原式=sin(π/6-α)+sin(π/6+α）
=2sin0.5*[(π/6-α)+(π/6+α)] cos0.5[(π/6-α)-(π/6+α)]
=2sin π/6 cosα
=cosα
cos(π/3+α)+sin(π/6+α)
=cosπ/3cosα-sinπ/3sinα+sinπ/6cosα+cosπ/6sinα
=1/2*cosα-√3/2*sinα+1/2*cosα+√3/2sinα
=cosα
把它展开cosπ/3cosa-sinπ/3sina+sinπ/6cosa+cosπ/6sina=cosπ/3cosa+sinπ/6cosa 把cosπ/6换成sinπ/6 这样等于2sinπ/6cosa=cosa
化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π)
化简cos(3/2π+π)sin(-π+α)
化简：cos(π/3+α)+sin(π/6+α)
化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)=
化简sin(α-3/2π)cos(α-π)-sin(α-2π)cos(α-π/2)=?
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α)
化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π)
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
化简：sinα-√3 cosα+2cos(α-π/3)
求值：（tan10°-√3）×cos10°/sin50° 求证：[sin（2α+β）]/sinα- 2cos（α+β）=sinβ/cosα 化简cosθ+cos（θ+2π/3）+cos（θ+4π/3） 证明：sin（α+β）sin（α-β）=sin^2α-sin^2β
化简：2sinα^2cosα-sin（3/2π-α）cos2α=
利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ