函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期
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函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期函数f(x)=sin(2x-π/4)-2根号2sin^2x的
函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期
函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期
函数f(x)=sin(2x-π/4)-2根号2sin^2x的最小正周期
f(x)=sin2x*cospi/4-cos2x*sinpi/4-根2(1-cos2x)=(根2/2)sin2x+(根2/2)cos2x-根2
=sin(2x+pi/4)-根2
最小正周期为pi
π啊
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