求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
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求证:sinx+siny=2sin(x+y)/2cos(x-y)/2求证:sinx+siny=2sin(x+y)/2cos(x-y)/2求证:sinx+siny=2sin(x+y)/2cos(x-y)
求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
x=(x+y)/2+(x-y)/2
y=(x+y)/2-(x-y)/2
sinx+siny=sin[(x+y)/2+(x-y)/2]+sin[(x+y)/2-(x-y)/2]
=sin(x+y)/2cos(x-y)/2+cos(x+y)/2sin(x-y)/2+sin(x+y)/2cos(x-y)/2-cos(x+y)/2sin(x-y)/2
=2sin(x+y)/2cos(x-y)/2
求证sin(2x+y)/sinx-2cos(x+y)=siny/sinx
求证:sin(2x+y)/sinx-2cos(x+y)=siny/sinx
求证sinx+siny=2sin(x+y)/2*cos(x-y)/2
求证:sinx+siny=2sin(x+y)/2cos(x-y)/2
求证|sinx-siny|=|2sin[(x-y)/2]cos[(x+y)/2]|
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证明sin(x+y)sin(x-y)=(sinx)^2-(siny)^2.
证明cosx(cosx-cosy)+sinx(sinx-siny)=2sin(x-y)/2
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为什么sinx*cosy-cosx*siny=sin(x-y)
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存在sin( x -y) = sinX-sinY吗
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请问,如何证明sinx+siny=2*sin(x+y/2)*cos(x-y/2)