此电路的电路分析,求大神指导R1 = 4K7R2, R8 = 1MR3, R4, R9, R10, R11, R12, R13 = 100KR5 = 1KR6, R7 = 470KR14, R15 = 220C1 = 22 pC2 = 82 pC3, C4, C5, C6 = 220nIC1 = 4521IC2 = 4017D1, D2, D4 = 1N4148cristal = 4.1943 MhzD3 = LED 3 mm2 x IC so
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此电路的电路分析,求大神指导R1=4K7R2,R8=1MR3,R4,R9,R10,R11,R12,R13=100KR5=1KR6,R7=470KR14,R15=220C1=22pC2=82pC3,C4
此电路的电路分析,求大神指导R1 = 4K7R2, R8 = 1MR3, R4, R9, R10, R11, R12, R13 = 100KR5 = 1KR6, R7 = 470KR14, R15 = 220C1 = 22 pC2 = 82 pC3, C4, C5, C6 = 220nIC1 = 4521IC2 = 4017D1, D2, D4 = 1N4148cristal = 4.1943 MhzD3 = LED 3 mm2 x IC so
此电路的电路分析,求大神指导
R1 = 4K7
R2, R8 = 1M
R3, R4, R9, R10, R11, R12, R13 = 100K
R5 = 1K
R6, R7 = 470K
R14, R15 = 220
C1 = 22 p
C2 = 82 p
C3, C4, C5, C6 = 220n
IC1 = 4521
IC2 = 4017
D1, D2, D4 = 1N4148
cristal = 4.1943 Mhz
D3 = LED 3 mm
2 x IC sockets 16 pin
求大神指导
此电路的电路分析,求大神指导R1 = 4K7R2, R8 = 1MR3, R4, R9, R10, R11, R12, R13 = 100KR5 = 1KR6, R7 = 470KR14, R15 = 220C1 = 22 pC2 = 82 pC3, C4, C5, C6 = 220nIC1 = 4521IC2 = 4017D1, D2, D4 = 1N4148cristal = 4.1943 MhzD3 = LED 3 mm2 x IC so
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应用叠加定理,当只存在一个电流源的时候,此电路如何分析.求大神指导,谢谢
此电路的电路分析,求大神指导R1 = 4K7R2, R8 = 1MR3, R4, R9, R10, R11, R12, R13 = 100KR5 = 1KR6, R7 = 470KR14, R15 = 220C1 = 22 pC2 = 82 pC3, C4, C5, C6 = 220nIC1 = 4521IC2 = 4017D1, D2, D4 = 1N4148cristal = 4.1943 MhzD3 = LED 3 mm2 x IC so
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