select ** from A where A.id in (select id from B where ****) 在以下哪种情况,select ** from A whereselect ** from A where A.id in (select id from B where ****) 在以下哪种情况,此语句执行的速度快:(1)A表的记录数远多于

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select**fromAwhereA.idin(selectidfromBwhere****)在以下哪种情况,select**fromAwhereselect**fromAwhereA.idin(s

select ** from A where A.id in (select id from B where ****) 在以下哪种情况,select ** from A whereselect ** from A where A.id in (select id from B where ****) 在以下哪种情况,此语句执行的速度快:(1)A表的记录数远多于
select ** from A where A.id in (select id from B where ****) 在以下哪种情况,select ** from A where
select ** from A where A.id in (select id from B where ****) 在以下哪种情况,此语句执行的速度快:(1)A表的记录数远多于B表的记录数;(2)A表的记录数远小于B表的记录数
当B表拥有很好的索引,不考虑两个表之间的连接速度,上面哪种情况,语句的执行的速度快

select ** from A where A.id in (select id from B where ****) 在以下哪种情况,select ** from A whereselect ** from A where A.id in (select id from B where ****) 在以下哪种情况,此语句执行的速度快:(1)A表的记录数远多于
相对来说第一种情况快,sql查询的顺序是先查where 后面的结果,那么如果B表数据少,当然速度相对要快于数据多的情况.实际情况用内连接速度会快得多.

sql如何取交集有这样两条sql语句select distinct id from a where id='123'select distinct id from a where id='456'我希望能把他们取得他们记录的交集,sql语句该如何写?错了 应该是这样的select distinct temid from a whe select * from a union select * from b 能详细说下么 select * into b from a where 11 select * from (select a.*,rownum aa from table a ) where aa=10 select *from A where A.a like '%1%'||'%' Please select a city or zipcode from the drop-down. Please select a plan from the options to the select * from book limit , insert into a select * from b 和select * into a from b 这两个语句是不是一样的? select id from (select id from pedigree group by number having count(name)>1)as a; 为啥用as a select c.*,d* from ( select 图号 from ( SELECT a.*,b.存货编码 FROM 未明图号 as a left OUTER JOIN 存select c.*,d* from ( select 图号 from (SELECT a.*,b.存货编码FROM 未明图号 as a left OUTER JOIN 存货档案 as bON a.图号=b.规 select from 表 和select from [表]有什么不同? select count(*) from 怎么使用 select count(1) from emp select * into dept2 from dept HQL 的语法:select a from a where a=3 or select b from b whereb=2 要怎么写? select * from tb1 a where =(select min(id2) from tb1 where id1=a.id1)其中的a该如何理解? 帮我看看这个oracle语句,select groupid,parentid,groupname,isleaf,description,sharerankid,statusid,corporationid,staffid,isactual,groupcount,level FROM (SELECT a.*,b.groupcount FROM teabgroup a,(SELECT groupid,count(*) groupcount FROM teabmembe