(1) [(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0 (2) (2lg2+lg3)/1+1/2lg0.36+1/4lg16
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 00:23:45
(1)[(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0(2)(2lg2+lg3)/1+1/2lg0.36+1/4lg16(1)[(0.064*1/5)^-2.5]2/3-3根号3又
(1) [(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0 (2) (2lg2+lg3)/1+1/2lg0.36+1/4lg16
(1) [(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0 (2) (2lg2+lg3)/1+1/2lg0.36+1/4lg16
(1) [(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0 (2) (2lg2+lg3)/1+1/2lg0.36+1/4lg16
(2)2㏒6+㏒√0.36+㏒2
2㏒6+㏒1.2
2㏒7.2
第一题写的不清楚!
6.25,2.5,1,(),(),0.064
找规律填数:6.25 2.5 1 ( ) ( ) 0.064
找规律 6.25 2.5 1 ( )( ) 0.064
找规律6.25 2.5 1 ()()0.064
找规律 6.25 2.5 1 ( ) ( ) 0.064
6.25 2.5 1 ( ) ( ) 0.064找规律填数
6.25、2.5、1、()、()、0.064是什么规律?
按规律填空. 6.25, 2.5, 1 ( ) ( ) 0.064
按规律添数:6.25,2.5,1,()()0.064
(1) [(0.064*1/5)^-2.5]2/3-3根号3又3/8-π^0 (2) (2lg2+lg3)/1+1/2lg0.36+1/4lg16
求出下列各正数的平方根、负数的立方根1又7/9(-1/2)²-0.064(-1/5)³
计算,(1)(0.064)^1/3-(-5/9)^0+[(-2)^3]^-4/3+16^-0.75(2)1/2lg25+lg2-lg根号0.1-log29*log32求解过程.
(0.064)^-1/3-(-7/8)^0+[(-2)^5]^-2/5+(1/16)^0.75=?
6.25 2.5 1 --- --- 0.064找规律
找规律 :1、0.4、0.16、0.064、【 】
(0.064)^-1/3-(-7/8)^0+[(-2)^3]^-4/3+16^-0.75+0.01^1/2
(0.064)^-1/3-(-7/8)^0+[(-2)^3]^-4/3+16^-0.75+0.01^1/2
求值(0.064)∧-1/3-(1/2√2)∧-2÷16∧0.75