已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S13=1,则a1=?
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已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S13=1,则a1=?已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S
已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S13=1,则a1=?
已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S13=1,则a1=?
已知数列an满足an=(an-1)-(an-2)(n≥3,n∈N)它的前n项和为Sn,若S13=1,则a1=?
由递推式可知前十三项为:
a1,a2,a2-a1,a3-a2……,a11-a10,a12-a11
相加得S13=a2+a12=1
而a12=a11-a10
=a10-a9-a10
=-a9
=-(a8-a7)
=a7-(a7-a6)
=a6
=a5-a4
=a4-a3-a4
=-a3
=a1-a2
所以a2+a12=a2+a1-a2=a1=1
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