已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
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已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an已知数列{an}满足a1=1,a2=3,an+2=3
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
由an+2=3an+1-2an 可得an+2-an+1=2(an+1-an)
因为a2-a1=2,所以an+1-an不会等于0,则an+1-an是以2为公比的等比数列
由上可得an+1-an=2^n
an-an-1=2^(n-1)
.
.
a2-a1=2
连加可得an+1=2^(n+1)-1
则an=2^n-1
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