计算(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)

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计算(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)
计算(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)

计算(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)
(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)
=x²-2x-3-x²-4x-4+x²-4
=x²-6x-11

(x+1)(x-3)-(x+2)的平方+(x+2)(x-2)
=(x+1)(x-3)-(x+2)(x+2-x+2)
=(x+1)(x-3)-4(x+2)
=xx-2x-3-4x-8
=xx-6x-11