试确定(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1的末位数字
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试确定(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1的末位数字
试确定(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1的末位数字
试确定(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1的末位数字
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)/(2-1)+1
=(2^128-1)+1
=2^128
2^1=2
2^2=4
2^3=8
2^4个位数是6
2^5个位数是2
所以个位数是4个一循环
所以2^128的个位数=2^4的个位数=6
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
......
=2^128
2^1=2,2^2=4,2^3=8,2^4=16,2^5=32
末位数4个一循环
所以为尾数为6
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)/(2-1)+1
=(2^128-1)+1
=2^128
2^1=2
2^2=4
2^3=8
2^4个位数是6 ...
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(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)/(2-1)+1
=(2^128-1)+1
=2^128
2^1=2
2^2=4
2^3=8
2^4个位数是6
2^5个位数是2
所以个位数是4个一循环
所以2^128的个位数=2^4的个位数=6
回答者： 我不是他舅 - 总兵 十一级 12-28 19:38
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1
......
=2^128
2^1=2,2^2=4,2^3=8,2^4=16,2^5=32
末位数4个一循环
所以为尾数为6
回答者：魔痕炫影 - 初入江湖 三级 12-28 19:40
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回答者：一切都是我 - 试用期 一级 12-30 09:19
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