1/1×3+1/3×5+……+1/9×11=简便运算
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1/1×3+1/3×5+……+1/9×11=简便运算1/1×3+1/3×5+……+1/9×11=简便运算1/1×3+1/3×5+……+1/9×11=简便运算1/(1×3)+1/(3×5)+……+1/(
1/1×3+1/3×5+……+1/9×11=简便运算
1/1×3+1/3×5+……+1/9×11=简便运算
1/1×3+1/3×5+……+1/9×11=简便运算
1/(1×3)+1/(3×5)+……+1/(9×11)
=1/2×(1-1/3)+1/2×(1/3-1/5)+……+1/2×(1/9-1/11)
=1/2×(1-1/3+1/3-1/5+……+1/9-1/11)
=1/2×(1-1/11)
=1/2×10/11
=5/11
明白请采纳,
有新问题请求助,
1/n(n+2)=[1/n-1/(n+2)]/2
1/1×3+1/3×5+……+1/9×11=(1-1/3)/2+(1/3-1/5)/2+....+(1/9-1/11)/2=(1-1/3+1/3-1/5+....+1/9-1/11)/2=(1-1/11)/2=10/11x2=5/11
1+3+5+7+9+……+(2n-1)
(1+1/1*3)(1+1/2*4)(1+1/3*5)……(1+1/9*11)找规律
1/3×1/5+1/5×1/7+1/7×1/9+……+1/97×1/99
1+1/1*3+1/3*5+1/5*7+1/7*9+……+1/99*101=?
1/1×3+1/3×5+……+1/9×11=简便运算
计算1/1*3+1/2*4+4/3*5+……+1/9*11
1+2+3+4+5+67+8+9………………100=
1/3*5+1/5*7+1/7*9+……1/97*99
计算:1/1*3+1/3*5+1/5*7+1/7*9+……+1/97*99=
1/1×3+1/3×5+1/5×7+1/7×9……1/97×99算式,
1/1*3+1/3*5+1/5*7+1/7*9……+1/99*101等于多少?
1/1*3+1/3*5+1/5*7+1/7*9……1/2007*2009
下面是按“塔”形排列的一组数:1-1/2 1/3 -1/4 1/5 -1/6-1/7 1/8 -1/9 1/10 ……………………………………………………….那么第200行第5个数是请写出规律
1-3+5-7+9-11……2007-2009?
1+3+5+7+9+……+97+99是多少?
计算1-3+5-7+9……-1999+2001
计算1+3+5+7+9+……+201
1-3+5-7+9-11……+97-99