复数i/(2+i)=

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复数i/(2+i)=复数i/(2+i)=复数i/(2+i)=i/(2+i)=[i(2-i)]/[(2+i)(2-i)]=(2i+1)/5额上下乘以(2-i）=i(2-i)/(4-i^2)=(2i+1)

复数i/(2+i)=
复数i/(2+i)=

复数i/(2+i)=
i/(2+i)
=[i(2-i)]/[(2+i)(2-i)]
=(2i+1)/5

额

上下乘以(2-i）=i(2-i)/(4-i^2)=(2i+1)/5

复数i/(2+i)= 复数i/2+i= 复数(2i/1+i)^2=? 复数 i-2/1+2i= 复数(i-2)/(i+2)=? 复数2-2i/1+i=? 复数 (3-i/1+i)^2= 复数(1-i)^2/1+i= 复数：5i/1-2i=? 复数1+3i/2+i= 复数1+i/2i-1= 复数-2+i/1+i= 复数(4+3i)(2+i)= 复数8+6i/2i= 复数满足i/z+i=2-i ,z=? 计算复数z=(2-i)/(1-i)-i 复数1-i/i=? 复数相乘 (-i)i=?