1/3x^2+2/3xy+1/3y^2
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1/3x^2+2/3xy+1/3y^21/3x^2+2/3xy+1/3y^21/3x^2+2/3xy+1/3y^2=1/3(X+Y)^2
1/3x^2+2/3xy+1/3y^2
1/3x^2+2/3xy+1/3y^2
1/3x^2+2/3xy+1/3y^2
=1/3(X+Y)^2
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已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎