化简：sqr[1/2-1/2*sqr(1/2+1/2*cos2a)] a属于(3π/2,2π)

请问sqr(1+sqr(2+sqr(3+sqr(4+sqr(5+sqr(6+.sqr(1+sqr(2+sqr(3+sqr(4+sqr(5+sqr(6+.一直到n...如何在vb实现..... 1+1/sqr(2)+1/sqr(3)+1/sqr(4)+.+1/sqr(n)=? lim((sqr(2)-sqr(1+cosx))/((sinx)^2)) x->0 1/4+SQR[5A]+30SQR[2]+1/3-SQR[66-40SQR[2]] 怎么计算啊? 化简：sqr[1/2-1/2*sqr(1/2+1/2*cos2a)] a属于(3π/2,2π) 为什么sqr(n^2+a^2)/n = sqr[1+(a/n)^2] 求y=sqr(2x+2)+sqr(1-x)的值域RT 求值域:y=1/(sqr(4-x)-sqr(x-2)) 为什么sqr(x^3+1)-sqr(x^3) =……sqr(x^3+1)-sqr(x^3) =1/(sqr(x^3+1)+sqr(x^3)) 请问 #define sqr(x) x*x K=2,M=1 sqr(k+m)/sqr(k+m)为什么结果是7 化简sqr(4+2sqr3) 三道积分问题~ (1) S sqr (x^2(1) S sqr (x^2-25)/x dx =?(2) S 1/(X sqr(x^2+1)) dx =?(3) S x/(sqr(x^2+4x+13)) dx =? log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 ∫ln(x+sqr(x^2+1))dx 积分∫x^3*sqr(1-x^2)dx f(x)=sqr(x^2+1),求不定积分 不定积分x^3/sqr(1+x^2)^3 dx