(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
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(x+2)/x(x-2)-(x-1)/x²-4x+4=几,(x+2)/x(x-2)-(x-1)/x²-4x+4=几,(x+2)/x(x-2)-(x-1)/x²-4x+4=
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
(x+2)/[x(x-2)] - (x-1)/(x²-4x+4)
=(x+2)/[x(x-2)] - (x-1)/(x-2)²
=[(x+2)(x-2)- x(x-1)]/[x(x-2)²]
=(x²-4-x²+1)/[x(x-2)²]
=-3/[x(x-2)²]
(x+2)/x(x-2)-(x-1)/(x²-4x+4)
=(x+2)(x-2)/x(x-2)((x-2)-x(x-1)/x(x-2)²
=[(x²-4)-(x²-x)]/x(x-2)²
=(x-4)/x(x-2)²老师的答案是3/（x-2）不管你老师的答案是什么，反正根据你给的题目算出的就是这样一个结果：=(x-...
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(x+2)/x(x-2)-(x-1)/(x²-4x+4)
=(x+2)(x-2)/x(x-2)((x-2)-x(x-1)/x(x-2)²
=[(x²-4)-(x²-x)]/x(x-2)²
=(x-4)/x(x-2)²
收起
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×[x/(x-4)]
=[(x²-4-x²+x)/x(x-2)²]×[x/(x-4)]
=[(x-4)/x(x-2)²]×[x/(x-4)]
=1/(x-2)²
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