1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?
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1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?2/3*
1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?
1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?
1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?
2/3*4^(n+1)*(n+1)-8/9*4^(n+1)+8/9
为等差和等比
1x2^3+2x2^5+3x2^7+…+nx2^2n+1是多少?
2^5+5x2^4+10x2^3+10x2^2+5x2+1
求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708
4x2-3y2+2xy-4x2+5x2
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21x2是x的平方
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
若 x2-3x+1=0,求(2x2×x3-5x2×x2+2 x3-8x2 )÷(x2+1 )的值
用杨辉三角规律计算下题 2^5-5x2^4+10x2^3-10x2^2+5x2-1
观察一列单项式:1x,3x2,5x2,7x,9x2,11x2第N个呢?
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
5x2—[x2+(4x—x2)—2(x2—3x)]
已知x2-4x+1=0,求x2/(x2)2-3x2+1
Sn=1x2+3x2^2+5x2^3+...+(2n-1)2^n
3x2-【7x2-(2x2-1)】其中x=-1/2 先化简,在求值
解方程:(X2+2)/(2X2-1)-3(2X2-1)/(X2+2)+2=0 3x2+15x+2根号下(x2+5x+1)=2(X2+2)/(2X2-1)-3(2X2-1)/(X2+2)+2=03x2+15x+2根号下(x2+5x+1)=2
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708等会就要 再次坐等
求和1x2+3x2^2+5x2^3+…+(2n-1)x2n要详解答案,我采纳!急用!