已知在等边三角形ABC中,D,E分别是BC,AC上的点,且AE=CD,连接AD、BE交与点P,做BQ⊥AD,垂足为Q.求证BP＝2PQ
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已知在等边三角形ABC中,D,E分别是BC,AC上的点,且AE=CD,连接AD、BE交与点P,做BQ⊥AD,垂足为Q.求证BP＝2PQ
已知在等边三角形ABC中,D,E分别是BC,AC上的点,且AE=CD,连接AD、BE交与点P,做BQ⊥AD,垂足为Q.求证BP＝2PQ
已知在等边三角形ABC中,D,E分别是BC,AC上的点,且AE=CD,连接AD、BE交与点P,做BQ⊥AD,垂足为Q.求证BP＝2PQ
因为△BEA≌△ADC. ∠APE=∠ABE+∠BAP ∠ABE=CAD 由于是等边三角形∠BAD+∠CAD=60° 所以∠BAD+∠ABD=60° 所以∠APE＝60° =∠BPQ 剩下的你自己该知道怎么回事了吧.直角三角形有一个角为60.
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Love the color
Why
ethereal rain
always brought back sad memories
Why
distant siren
always think your night sing...
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,mbt chaussures paris
Love the color
Why
ethereal rain
always brought back sad memories
Why
distant siren
always think your night singing
Why
holy emotions flowing inside the tiny Qingsi
wilting flowers will bloom again when the situation
join hands
faith and love beyond time and space scale
an ellipsis I see a zoom in
own romantic
yesterday in a swirl of love dance
cabinet photos
padding I lost the memory of an angel -like
smile
you want to feel the warm breath close to
expect all that is sweet
rose has opened the hearts of
I read it is because the color of love
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