4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] 第2第3项 怎么处理的?
来源：学生作业帮助网 编辑：六六作业网 时间：2024/07/04 20:35:54
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16]第2第3项怎么处理的?4^log(4)[x^2]+3^log(9)[6x]=log(2)[16]第2第3项怎么处理的?4^lo
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] 第2第3项 怎么处理的?
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16]
第2第3项 怎么处理的?
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] 第2第3项 怎么处理的?
比如log(9)a=log(3)a/[log(3)9]=log(3)a/2=log(3)[a^1/2]换底公式
而log(2)[16]=log(2)[2^4]=4log(2)2=4
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] x
x²+3x=4x
x²=7x
x=7或x=0（舍去）
已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
(log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0
log(2)(x)log(2)(4x)-3log(2)(x)-12=0
2 log(3x)= log 4 +log(6-x)怎么求...急
已知log(2){log(3)[log(4)(x)]}=5^0,则x=?
4^[log(2)3+log(4)8]
log(2)9log(3)4等于
log(2)9×log(3)4
若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z=
对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(2)(3)} X {log(3)(4)+log(9)(2)}3.(lg2)^+1g2X 1g5 +1g50
log(2)(x+4)=3^x
化简log(2)3 * log(3)4 * log(4)7 *log(7)16
化简:(log^3 2+log^9 2)(log^4 3+log^8 3)
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路
log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃....
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
求等式log(2)3*log(3)4*log（4)5*log(5)6*log(6)7*log(7)m=log(3)9时m的值?