x+y+z=35 y=2x-5 1/3y=1/2z 三元一次的方程
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x+y+z=35y=2x-51/3y=1/2z三元一次的方程x+y+z=35y=2x-51/3y=1/2z三元一次的方程x+y+z=35y=2x-51/3y=1/2z三元一次的方程x+y+z=35①y
x+y+z=35 y=2x-5 1/3y=1/2z 三元一次的方程
x+y+z=35 y=2x-5 1/3y=1/2z 三元一次的方程
x+y+z=35 y=2x-5 1/3y=1/2z 三元一次的方程
x+y+z=35 ①
y=2x-5 ②
y/3=z/2 ③
由③得 y=1.5z
将y=1.5z代入①②中得:
x+2.5z=35
1.5z=2x-5
解上述二元一次方程得:x=10 z=10
故 x=10
y=15
z=10
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{x:y=2:3 y:z=4:5 x+y+z=35
x:y=2:3 y:z=4:5 x+y+z=35
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