(x+3)(x-4)(x+5)(x-6)+80因式分解,

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(x+3)(x-4)(x+5)(x-6)+80因式分解,(x+3)(x-4)(x+5)(x-6)+80因式分解,(x+3)(x-4)(x+5)(x-6)+80因式分解,答:原式=[(x+3)(x-4)

(x+3)(x-4)(x+5)(x-6)+80因式分解,
(x+3)(x-4)(x+5)(x-6)+80因式分解,

(x+3)(x-4)(x+5)(x-6)+80因式分解,
答:
原式
=[(x+3)(x-4)][(x+5)(x-6)]+80
=(x²-x-12)(x²-x-30)+80
=(x²-x)²-42(x²-x)+360+80
=(x²-x)²-42(x²-x)+440
=(x²-x)²-42(x²-x)+(-22)×(-20)
=(x²-x-22)(x²-x-20)
=(x²-x-22)(x-5)(x+4)

(x+3)(x-4)(x+5)(x-6)+80
=(x²-x-12)(x²-x-30)+80
=(x²-x-12)[(x²-x-12)-18]+80
=(x²-x-12)²-18(x²-x-12)+80
=[(x²-x-12)-8][(x²-x-12)-10]
=(x&...

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(x+3)(x-4)(x+5)(x-6)+80
=(x²-x-12)(x²-x-30)+80
=(x²-x-12)[(x²-x-12)-18]+80
=(x²-x-12)²-18(x²-x-12)+80
=[(x²-x-12)-8][(x²-x-12)-10]
=(x²-x-20)(x²-x-22)
=(x-5)(x+4)[(x-1/2)² -89/4]
=(x-5)(x+4)[x-(1+√89)/2][x-(1-√89)/2]

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原式=﹙x²-x-12﹚﹙x²-x-30﹚+80
设x²-x-12=y
原式=y﹙y-18﹚+80
=y²-18y+80
=﹙y-8﹚﹙y-10﹚
把y=x²-x-12代人上式:
原式=﹙x²-x-12-8﹚﹙x...

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原式=﹙x²-x-12﹚﹙x²-x-30﹚+80
设x²-x-12=y
原式=y﹙y-18﹚+80
=y²-18y+80
=﹙y-8﹚﹙y-10﹚
把y=x²-x-12代人上式:
原式=﹙x²-x-12-8﹚﹙x²-x-12-10﹚
= ﹙x²-x-20﹚﹙x²-x-22﹚
=﹙x+4﹚﹙x-5﹚﹙x²-x-22﹚

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