lim 1/[(sinx)^2-x^2]= x->0如题

lim(x+e^2x)^(1/sinx) lim (e^x-sinx-1)/(arcsinx^2) 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 lim [xtan(2/x)+(1/x^2)sinx^2] . lim（2x+1）sinx/2/x+2= lim((e^2-1-x)^2)/(x(sinx^3)) lim(x→0)(1+sinx)^(1/2x) 怎么计算lim(x->0+)x^(1/2)*ln(sinx)? lim(x趋向0)((sinx/x)+1)=2? lim(x-->0) (e^(2x)-1)/sinx Lim x趋向零 (sinx/x)^1/2 求极限lim(x→0) (1-sinx)^(2/x) 求极限 lim(x→0)(1-sinx)^(2/x) x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you lim(x->无穷大)x/(sinx)^2=? lim (x^2sin1/x) /sinx lim x趋向0 x^2-sinx/x+sinx lim（x-0） x｀2-sinx/x+sinx